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<math> \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] </math>
 
<math> \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] </math>
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<math> \,\ H[z] =

Revision as of 16:10, 25 September 2008

Define a DT LTI System

$ \,\ x[n] = 5*u[n-5] + 6*u[n+6] $

h[n] and H(z)



We obtain $ h[n] $ by finding the response of $ x[n] $ to the unit impulse response ($ \delta[n] $).

$ \,\ h[n] = 5*\delta[n-5] + 6*\delta[n+6] $

$ \,\ H[z] = $

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Ryne Rayburn