Difference between revisions of "HW4.3 Xujun Huang ECE301Fall2008mboutin" - Rhea

Revision as of 12:20, 25 September 2008

LTI System: $y(t) = Kx(t)\,$ where K is a constant

Unit Impulse Response: $h(t) = K \delta(t)\,$

Frequency Response:

$H(s) = \int^{\infty}_{-\infty} h(\tao)e^{-j\omega_0 r} d\tao$ by definition

@@ Line 5: / Line 5: @@
 Frequency Response:
-<math>y(t) = \int^{\infty}_{-\infty} h(t) * x(t) dt\,</math> where <math>x(t) = 1+\sin \omega_0 t + \cos(2\omega_0 t+ \frac{\pi}{4})</math>
+<math>H(s) = \int^{\infty}_{-\infty} h(\tao)e^{-j\omega_0 r} d\tao</math> by definition
-<math>y(t) = \int^{\infty}_{-\infty} K \delta(t) * (1+\sin \omega_0 t + \cos(2\omega_0 t+ \frac{\pi}{4}))</math>