| Line 8: | Line 8: | ||
<math>h(t) = 5u(t-3)</math> | <math>h(t) = 5u(t-3)</math> | ||
| + | |||
| + | <math>H(s) = 5\int_3^\infty e^{-st}dt</math> | ||
| + | |||
| + | <math>H(s) = \frac{-5}{s} </math> | ||
| + | |||
| + | <math>4 to \infty</math> | ||
| + | |||
| + | <math>H(s)= \frac {5}{s}</math> | ||
Revision as of 19:34, 25 September 2008
part A
$ e^{st}\rightarrow h(t)\rightarrow H(S)e^{st} $
$ H(s) = \int_{-\infty}^\infty h(t)e^{-st}dt $
assume
$ h(t) = 5u(t-3) $
$ H(s) = 5\int_3^\infty e^{-st}dt $
$ H(s) = \frac{-5}{s} $
$ 4 to \infty $
$ H(s)= \frac {5}{s} $
