Revision as of 17:06, 26 September 2008 by Sje (Talk)

Given the system $ y(t) = 2x(t+3)\, $

$ x(t)= 2\delta(t+3) $

Then find the response to $ x(t) = cos(4t) + sin(2t)\, $

$ x(t)=\frac{1}{2}e^{j4\pi t}+\frac{1}{2}e^{-j4\pi t}+\frac{1}{2j}e^{j2\pi t}+\frac{-1}{2j}e^{-j2\pi t} $

$ H(j\omega)=\int_{-\infty}^\infty h(\tau)e^{-j\omega\tau}d\tau $

$ H(j\omega)=\int_{-\infty}^\infty (2\delta(\tau+3))e^{-j\omega\tau}d\tau $

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