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<math>y(t) = \int^{\infty}_{-\infty} \delta(t) dt\,</math><br>
 
<math>y(t) = \int^{\infty}_{-\infty} \delta(t) dt\,</math><br>
 
<br>
 
<br>
<math>H(s)=\int_{-\infty}^{\infty}h(\tau)e^{-s\tau}=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau}</math><br>
+
<math>H(s)=\int_{-\infty}^{\infty}h(\tau)e^{-s\tau}</math><br>
 
<br>
 
<br>
 
<math>H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau}</math><br>
 
<math>H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau}</math><br>

Revision as of 08:06, 26 September 2008

Obtain the input impulse response h(t) and the system function H(s) of your system

A very simple system:
$ y(t)=x(t)\, $ and $ x(t)=\delta(t) $

We can get $ h(t)=\delta(t)\, $
$ y(t) = \int^{\infty}_{-\infty} \delta(t) dt\, $

$ H(s)=\int_{-\infty}^{\infty}h(\tau)e^{-s\tau} $

$ H(s)=\int_{-\infty}^{\infty}u(\tau)e^{-s\tau} $


Compute the response of your system to the signal you defined in Question 1 using H(s) and the Fourier series coefficients of your signal

Alumni Liaison

Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang