(RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1)
(RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1)
Line 29: Line 29:
 
<br>
 
<br>
  
To send the signal through the system, we must peform the following operations:
+
From question 1, we also know that:
 +
<br>
 +
<math>f(t) = ((3+j)\frac{e^{2jt}}{2} + (3+j)\frac{e^{-2jt}}{2} + (10+j)\frac{e^{7jt}}{2j} - (10+j)\frac{e^{-7jt}}{2j}\!</math>
 +
 
 +
 
 +
 
 +
UNDER CONSTRUCTION

Revision as of 12:37, 25 September 2008

CT LTI SYSTEM

I chose the following continusous-time linear time invariant system:

$ f(t) = \frac{7x(t)}{3} + \frac{9x(t+8)}{2}\! $

UNIT IMPULSE RESPONSE OF SYSTEM

To find the unit impulse response of the system, we set $ x(t) = \delta(t)\! $. Then we obtain the following unit impulse response:


$ h(t) = \frac{7\delta(t)}{3} + \frac{9\delta(t+8)}{2}\! $


THE SYSTEM FUNCTION

In order to compute the system function H(s), we can simply take the laplace transform of the unit impulse response of the system. When we take the laplace transform, we find that $ H(s) = \frac{7}{3} + \frac{9e^{-8jw}}{3}\! $


RESPONSE OF SYSTEM TO SIGNAL DEFINED IN QUESTION 1

In question 1, I used the following signal: $ f(t) = (3+j)cos(2t) + (10+j)sin(7t)\! $


From question 1, we also know that:
$ f(t) = ((3+j)\frac{e^{2jt}}{2} + (3+j)\frac{e^{-2jt}}{2} + (10+j)\frac{e^{7jt}}{2j} - (10+j)\frac{e^{-7jt}}{2j}\! $


UNDER CONSTRUCTION

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett