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| − | == CT LTI system == | + | == CT LTI system Part a == |
| + | :<math> h(t) = e^{-t}u(t)</math><br><br> | ||
| + | :<math> H(jw) = \int_0^{\infty} e^{-\tau}e^{-jw{\tau}}\,d{\tau} </math> | ||
| + | :::<math> = [-{1 \over 1 + jw}e^{-\tau}e^{-jwr} ]^{\infty}_0 </math><br><br> | ||
| + | :::<math> = {1 \over 1+ jw}</math><br><br><br> | ||
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| + | |||
| + | == CT LTI system Part b == | ||
| + | <math>y(t) = \sum_{i=m}^n x_i = x_m + x_{m+1} + x_{m+2} +\dots+ x_{n-1} + x_n. </math> | ||
Revision as of 17:13, 26 September 2008
Preview
This is only a preview; changes have not yet been saved! (????)
CT LTI system Part a
- $ h(t) = e^{-t}u(t) $
- $ H(jw) = \int_0^{\infty} e^{-\tau}e^{-jw{\tau}}\,d{\tau} $
- $ = [-{1 \over 1 + jw}e^{-\tau}e^{-jwr} ]^{\infty}_0 $
- $ = {1 \over 1+ jw} $
- $ = [-{1 \over 1 + jw}e^{-\tau}e^{-jwr} ]^{\infty}_0 $
CT LTI system Part b
$ y(t) = \sum_{i=m}^n x_i = x_m + x_{m+1} + x_{m+2} +\dots+ x_{n-1} + x_n. $
