(Repsonse of the CT system)
 
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<math> y(t) = H(s)x(t)\,</math><br>
 
<math> y(t) = H(s)x(t)\,</math><br>
  
<math> y(t) = \frac{1}{j2}\frac{1}{2}e^{\frac{2j2\pi t}{6}} + \frac{1}{-j2}\frac{1}{2}e^{\frac{-2j2\pi t}{6}} \frac{1}{j5}-2je^{\frac{2j5\pi t}{6}} + \frac{1}{-j5}2je^{\frac{-2j5\pi t}{6}}</math>
+
<math> y(t) = \frac{1}{j4}e^{\frac{2j2\pi t}{6}} - \frac{1}{j4}e^{\frac{-2j2\pi t}{6}} - \frac{2}{5}e^{\frac{2j5\pi t}{6}} -\frac{2}{5}e^{\frac{-2j5\pi t}{6}}</math>

Latest revision as of 18:48, 25 September 2008

Unit Impulse

$ h(t) = u(t-1) \, $

$ H(s) = \int^{\infty}_{-\infty} u(t-1)e^{-jw_0 t} dt\, $

$ H(s) = \int^{\infty}_{1}e^{-jw_0 t} dt\, $

$ H(s) = \frac{1}{jw_0} $


Repsonse of the CT system

$ x(t) = cos({\frac{2\pi t}{3}})+ 4sin({\frac{5\pi t}{3}})\, $

$ y(t) = H(s)x(t)\, $

$ y(t) = \frac{1}{j4}e^{\frac{2j2\pi t}{6}} - \frac{1}{j4}e^{\frac{-2j2\pi t}{6}} - \frac{2}{5}e^{\frac{2j5\pi t}{6}} -\frac{2}{5}e^{\frac{-2j5\pi t}{6}} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood