Revision as of 17:40, 26 September 2008 by Jwise (Talk)

CT LTI signal:

$ y(t) = 3x(t-1)+x(t+3)-x(t)\! $


Part A

$ h(t) = 3\delta(t-1)+\delta(t+3)-\delta(t)\! $

$ H(j\omega) = \int_{-\infty}^{\infty}3\delta(t-1)+\delta(t+3)-\delta(t)\,dt\! $

$ H(s) = 3e^{-s} + e^{3s} - 1\! $

Part B

Alumni Liaison

Meet a recent graduate heading to Sweden for a Postdoctorate.

Christine Berkesch