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<math>\ a_{0} = b_{0} </math>
 
<math>\ a_{0} = b_{0} </math>
  
<math>\ b_{1} = a_{1} * (frac{1}{1+jw}
+
<math>\ b_{1} = a_{1} * \frac{1}{1+jw}

Revision as of 18:44, 26 September 2008

$ \ h(t) = 5e^{-t} $

$ \ H(jw) = 5\int_0^{\infty} e^{-\tau}e^{-jw{\tau}}\,d{\tau} $

$ \ H(jw) = 5[-\frac{1}{1 + jw}e^{-\tau}e^{-jwr} ]^{\infty}_0 $

$ \ H(jw) = \frac{5}{1+ jw} $

So,

$ \ a_{0} = b_{0} $

$ \ b_{1} = a_{1} * \frac{1}{1+jw} $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman