| Line 6: | Line 6: | ||
<math>\ H(jw) = \frac{5}{1+ jw} </math> | <math>\ H(jw) = \frac{5}{1+ jw} </math> | ||
| + | |||
| + | So, | ||
| + | |||
| + | <math>\ a_{0} = b_{0} </math> | ||
| + | |||
| + | <math>\ b_{1} = a_{1} * (1 / (1+jw) | ||
Revision as of 18:43, 26 September 2008
$ \ h(t) = 5e^{-t} $
$ \ H(jw) = 5\int_0^{\infty} e^{-\tau}e^{-jw{\tau}}\,d{\tau} $
$ \ H(jw) = 5[-\frac{1}{1 + jw}e^{-\tau}e^{-jwr} ]^{\infty}_0 $
$ \ H(jw) = \frac{5}{1+ jw} $
So,
$ \ a_{0} = b_{0} $
$ \ b_{1} = a_{1} * (1 / (1+jw) $
