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= <math>H(s) e^{st}</math>
 
= <math>H(s) e^{st}</math>
 +
 +
h(t) is the impulse response of the LTI SYSTEM
 +
H(s) is the system fuction
 +
 +
<math>H(s)= \int_{-\infty}^{\infty}h(T){e^{-sT}}\, dt </math>

Revision as of 15:46, 23 September 2008

A Signal for which the output signal  is constant times the input is referred as
an eigenfunction of the system,andthe amplitude is called the 
system's eigenvalue'

let the input be

$ x(t)= e^{st} $

we can determine the output using convolution integral

$ y(t)= \int_{-\infty}^{\infty}h(T)x(t-T)\, dt $

= $ \int_{-\infty}^{\infty}h(T){e^{s(t-T)}}\, dt $

= $ e^{st} \int_{-\infty}^{\infty}h(T){e^{-sT}}\, dt $

= $ H(s) e^{st} $

h(t) is the impulse response of the LTI SYSTEM H(s) is the system fuction

$ H(s)= \int_{-\infty}^{\infty}h(T){e^{-sT}}\, dt $

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