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we can determine  the output using convolution integral
 
we can determine  the output using convolution integral
  
<math>y(t)= int_{-\infty}^{\infty}h(T)x(t-T)\, dt </math>
+
<math>y(t)= \int_{-\infty}^{\infty}h(T)x(t-T)\, dt </math>

Revision as of 15:28, 23 September 2008

A Signal for which the output signal  is constant times the input is referred as
an eigenfunction of the system,andthe amplitude is called the 
system's eigenvalue'

let the input be

$ x(t)= e^{st} $

we can determine the output using convolution integral

$ y(t)= \int_{-\infty}^{\infty}h(T)x(t-T)\, dt $

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