m (DT signal & its Fourier Coefficients)
(DT signal & its Fourier Coefficients)
Line 3: Line 3:
 
<math>\ x[n] = 5sin(3 \pi n + \frac{4}{\pi})</math>
 
<math>\ x[n] = 5sin(3 \pi n + \frac{4}{\pi})</math>
  
<math>\ x[n] = \frac{5}{2j} (e^{j (3\pi n - \frac{4}{\pi})}-e^{-j (3\pi n - \frac{4}{\pi})})
+
<math>\ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{4}{\pi})}-e^{-j (3\pi n + \frac{4}{\pi})})

Revision as of 16:10, 26 September 2008

DT signal & its Fourier Coefficients

$ \ x[n] = 5sin(3 \pi n + \frac{4}{\pi}) $

$ \ x[n] = \frac{5}{2j} (e^{j (3\pi n + \frac{4}{\pi})}-e^{-j (3\pi n + \frac{4}{\pi})}) $

Alumni Liaison

ECE462 Survivor

Seraj Dosenbach