(Periodic CT Signal)
 
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[[Category:problem solving]]
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[[Category:ECE301]]
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[[Category:ECE]]
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[[Category:Fourier series]]
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[[Category:signals and systems]]
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== Example of Computation of Fourier series of a CT SIGNAL ==
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A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]]
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==Periodic CT Signal==
 
==Periodic CT Signal==
  
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<math>x(t) = \frac{e^{j(3\pi t+\pi)}+e^{-j(3\pi t+\pi)}}{2}</math>
 
<math>x(t) = \frac{e^{j(3\pi t+\pi)}+e^{-j(3\pi t+\pi)}}{2}</math>
  
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<math>    = \frac{e^{j3\pi t}e^{\pi}+e^{-j3\pi t}e^{\pi}}{2}</math>
  
<math>x(t) = \frac{4\pi}{3} + \frac{1}{j2000}(e^{j1000\pi t}+e^{j-1000\pi t}) - \frac{1}{j1000}(e^{j1000\pi t}-e^{j-1000\pi t})</math>
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<math>     = \frac{-e^{j3\pi t}-e^{-j3\pi t}}{2}</math>
  
==Fourier Series Coefficients==
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<math>     = -\frac{1}{2}e^{j3\pi t}-\frac{1}{2}e^{-j3\pi t}</math>
<math>a_0 = \frac{4\pi}{3}</math>
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<math>a_1 = \frac{1}{1000}</math>
 
  
<math>w_0 = 1000\pi\ </math>
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==Fourier Series Coefficients==
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<math>a_3 = -\frac{1}{2}</math>
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<math>a_{-3} = -\frac{1}{2}</math>
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----
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[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

Latest revision as of 11:08, 16 September 2013


Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


Periodic CT Signal

$ x(t) = cos(3\pi t+\pi) \! $ with fundamental frequency of $ \pi $


$ x(t) = \frac{e^{j(3\pi t+\pi)}+e^{-j(3\pi t+\pi)}}{2} $

$ = \frac{e^{j3\pi t}e^{\pi}+e^{-j3\pi t}e^{\pi}}{2} $

$ = \frac{-e^{j3\pi t}-e^{-j3\pi t}}{2} $

$ = -\frac{1}{2}e^{j3\pi t}-\frac{1}{2}e^{-j3\pi t} $


Fourier Series Coefficients

$ a_3 = -\frac{1}{2} $

$ a_{-3} = -\frac{1}{2} $


Back to Practice Problems on Signals and Systems

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