Revision as of 19:56, 21 September 2008 by Rwijaya (Talk)

CT Signal:
$ X(t) = 6\cos(2t) + 8\sin(4t)\, $
$ X(t) = 6\frac{e^{j2t}+e^{-j2t}}{2} + 8\frac{e^{j4t}-e^{-j4t}}{2}\, $
$ X(t) = 3(e^{j2t}+e^{-j2t}) + 4(e^{j4t}-e^{-j4t})\, $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood