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<br>
 
<math>X(t) = 6\cos(2t) + 8\sin(4t)\,</math><br>
 
<math>X(t) = 6\cos(2t) + 8\sin(4t)\,</math><br>
<math>X(t) = 6\frac{e^(j2t)+e^(-j2t)}{2} + 8\sin(4t)\,</math><br>
+
<math>X(t) = 6\frac{e^j2t\,+e^-j2t\,}{2} + 8\sin(4t)\,</math><br>

Revision as of 19:53, 21 September 2008

CT Signal:
$ X(t) = 6\cos(2t) + 8\sin(4t)\, $
$ X(t) = 6\frac{e^j2t\,+e^-j2t\,}{2} + 8\sin(4t)\, $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva