(New page: ==Define a periodic CT signal and compute its Fourier series coefficients.==)
 
 
(5 intermediate revisions by 2 users not shown)
Line 1: Line 1:
 +
[[Category:problem solving]]
 +
[[Category:ECE301]]
 +
[[Category:ECE]]
 +
[[Category:Fourier series]]
 +
[[Category:signals and systems]]
 +
== Example of Computation of Fourier series of a CT SIGNAL ==
 +
A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]]
 +
----
 +
 
==Define a periodic CT signal and compute its Fourier series coefficients.==
 
==Define a periodic CT signal and compute its Fourier series coefficients.==
 +
For CT,
 +
 +
<math>x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t}</math>
 +
 +
where
 +
 +
<math>a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt</math>.
 +
 +
Let the signal be
 +
 +
y(t) = 2*sin(2t)+2*cos(4t)
 +
 +
<math> y(t) = 2(\frac{e^{j2t} - e^{-j2t}}{2j}) + 2(\frac{e^{2j2t} + e^{-2j2t}}{2}) \!</math>
 +
 +
<math> a_1 = a_-1 = (\frac{1}{j})</math>
 +
 +
<math> a_2 = a_-2 = 1 </math>
 +
 +
a_k = 0 elsewhere
 +
----
 +
[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

Latest revision as of 10:56, 16 September 2013

Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


Define a periodic CT signal and compute its Fourier series coefficients.

For CT,

$ x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t} $

where

$ a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt $.

Let the signal be

y(t) = 2*sin(2t)+2*cos(4t)

$ y(t) = 2(\frac{e^{j2t} - e^{-j2t}}{2j}) + 2(\frac{e^{2j2t} + e^{-2j2t}}{2}) \! $

$ a_1 = a_-1 = (\frac{1}{j}) $

$ a_2 = a_-2 = 1 $

a_k = 0 elsewhere


Back to Practice Problems on Signals and Systems

Alumni Liaison

ECE462 Survivor

Seraj Dosenbach