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Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


Let $ x(t)=cos(4 \pi t) + sin(6 \pi t) $, then its Fourier series coefficients are as follows:

$ x(t)=\frac{e^{4 \pi jt} + e^{-4 \pi jt}}{2} + \frac{e^{6 \pi jt} + e^{-6 \pi jt}}{2j} $ and $ \omega_{0} = \pi $

$ a_{4} = a_{-4} = \frac{1}{2} $

$ a_{6} = -a_{-6} = \frac{1}{2j} $

All other $ a_{k} $ values are 0


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Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood