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HW4.1

periodic signal: $ \begin{align} x(t) = 32 + 8sin(2\pi t) + 22cos(2\pi t) + 2cos(2\pi t+\pi /2)\end{align} $

re-writing the signal in the form of $ \begin{align} e^{jw_0t} \end{align} $ we get $ \begin{align} x(t) = 32 + \frac{8}{2j} \left ( e^{j 2 \pi t} - e^{-j 2 \pi t} \right ) + 11 \left ( e^{j 2 \pi t} + e^{-j 2 \pi t} \right ) + \left ( e^{j 2 \pi t + \pi /2 } + e^{-j 2 \pi t + \pi /2} \right ) \end{align} $

then we can convert these to the coefficients of the Fourier series


$ \begin{align} a_0 = 32 \\ a_1 = 11 - 4/j \\ a_{-1} = 11 + 4/j \\ a_2 = e^{ \pi /2} \end{align} $

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Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

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