(New page: == HW4.1 == periodic signal: <math> \begin{align} x(t) = 32 + 8sin(2\pi t) + 22cos(2\pi t) + 2cos(2\pi t+\pi /2)\end{align} </math> re-writing the signal in the form of <math> \begin{alig...)
 
 
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[[Category:problem solving]]
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[[Category:ECE301]]
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[[Category:ECE]]
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[[Category:Fourier series]]
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[[Category:signals and systems]]
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== Example of Computation of Fourier series of a CT SIGNAL ==
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A [[Signals_and_systems_practice_problems_list|practice problem on "Signals and Systems"]]
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== HW4.1 ==
 
== HW4.1 ==
 
periodic signal: <math> \begin{align} x(t) = 32 + 8sin(2\pi t) + 22cos(2\pi t) + 2cos(2\pi t+\pi /2)\end{align} </math>
 
periodic signal: <math> \begin{align} x(t) = 32 + 8sin(2\pi t) + 22cos(2\pi t) + 2cos(2\pi t+\pi /2)\end{align} </math>
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\end{align}</math>
 
\end{align}</math>
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[[Signals_and_systems_practice_problems_list|Back to Practice Problems on Signals and Systems]]

Latest revision as of 11:05, 16 September 2013


Example of Computation of Fourier series of a CT SIGNAL

A practice problem on "Signals and Systems"


HW4.1

periodic signal: $ \begin{align} x(t) = 32 + 8sin(2\pi t) + 22cos(2\pi t) + 2cos(2\pi t+\pi /2)\end{align} $

re-writing the signal in the form of $ \begin{align} e^{jw_0t} \end{align} $ we get $ \begin{align} x(t) = 32 + \frac{8}{2j} \left ( e^{j 2 \pi t} - e^{-j 2 \pi t} \right ) + 11 \left ( e^{j 2 \pi t} + e^{-j 2 \pi t} \right ) + \left ( e^{j 2 \pi t + \pi /2 } + e^{-j 2 \pi t + \pi /2} \right ) \end{align} $

then we can convert these to the coefficients of the Fourier series


$ \begin{align} a_0 = 32 \\ a_1 = 11 - 4/j \\ a_{-1} = 11 + 4/j \\ a_2 = e^{ \pi /2} \end{align} $


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