(New page: ===Useful Info=== <math>x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t}</math> <math>a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt</math>. :Let :<math> x(t) = 2sin(2\pi t) + cos(\pi t)....)
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Revision as of 08:05, 25 September 2008

Useful Info

$ x(t)=\sum_{k=-\infty}^{\infty}a_ke^{jk\omega_0t} $

$ a_k=\frac{1}{T}\int_0^Tx(t)e^{-jk\omega_0t}dt $.

Let
$ x(t) = 2sin(2\pi t) + cos(\pi t). $

Solution

$ x(t) = 2\frac{e^{2 \pi jt}+e^{-2 \pi jt}}{2j} + \frac{e^{\pi jt}+e^{-\pi jt}}{2} $
$ x(t) = \frac{1}{j}(e^{2 \pi jt} + e^{-2 \pi jt}) + \frac{1}{2}(e^{\pi jt}+e^{-\pi jt}) $
$ a_1 = \frac{1}{j} $
$ a_2 = \frac{1}{2} $

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett