(→CT Signal) |
(→CT Signal) |
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:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}]</math><br><br> | :<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}]</math><br><br> | ||
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}]</math><br><br> | :<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}]</math><br><br> | ||
| − | :<math>e^{ | + | :<math>e^{j {\pi \over 4}} = {1 \over \sqrt{2}} + j{1 \over \sqrt{2}} </math><br> |
| − | :<math>e^{j{\pi \over 4}} = {1 \over \sqrt{2}} - j{1 \over \sqrt{2}} </math> | + | :<math>e^{-j{\pi \over 4}} = {1 \over \sqrt{2}} - j{1 \over \sqrt{2}} </math> |
<br><br> | <br><br> | ||
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}]</math><br><br> | :<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}]</math><br><br> | ||
| + | :<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2}({1 \over \sqrt{2}} + j{1 \over \sqrt{2}}) [e^{j w_0 t}]+ {3 \over 2}{1 \over \sqrt{2}} - j{1 \over \sqrt{2}} [e^{-j w_0 t}]</math><br><br> | ||
Revision as of 16:21, 26 September 2008
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CT Signal
- $ x(t) = 1 + sin(w_0 t) + 3cos(w_0 t + {\pi \over 4}) $
This is a signal with period $ T = {2\pi \over w_0} $
- $ x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}] $
- $ x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}] $
- $ e^{j {\pi \over 4}} = {1 \over \sqrt{2}} + j{1 \over \sqrt{2}} $
- $ e^{-j{\pi \over 4}} = {1 \over \sqrt{2}} - j{1 \over \sqrt{2}} $
- $ x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}] $
- $ x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2}({1 \over \sqrt{2}} + j{1 \over \sqrt{2}}) [e^{j w_0 t}]+ {3 \over 2}{1 \over \sqrt{2}} - j{1 \over \sqrt{2}} [e^{-j w_0 t}] $
