(New page: == Preview == This is only a preview; changes have not yet been saved! (????) == CT Signal == :<math> x(t) = 1 + sin(w_0 t) + 3cos(w_0 t + {\pi \over 4}) </math><br><br> This is a si...)
 
(CT Signal)
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This is a signal with period <math>T = {2\pi \over w_0}</math><br><br>
 
This is a signal with period <math>T = {2\pi \over w_0}</math><br><br>
 
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}]</math><br><br>
 
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}]</math><br><br>
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2}[e^{j w_0 t}e^ {{\pi \over 4}}+e^{-j w_0 t} e^{{\pi \over 4}}]</math><br><br>
+
:<math> x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}]</math><br><br>

Revision as of 16:10, 26 September 2008

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   This is only a preview; changes have not yet been saved! (????)

CT Signal

$ x(t) = 1 + sin(w_0 t) + 3cos(w_0 t + {\pi \over 4}) $

This is a signal with period $ T = {2\pi \over w_0} $

$ x(t) = 1 + {1 \over 2j}[e^{j w_0 t} - e^{-j w_0 t}] + {3 \over 2}[e^{(j w_0 t + {\pi \over 4})}+e^{-(j w_0 t + {\pi \over 4})}] $

$ x(t) = 1 + {1 \over 2j}[e^{j w_0 t}] + ({-1 \over 2j})e^{-j w_0 t} + {3 \over 2} [e^{j w_0 t}e^ {j{\pi \over 4}}]+ {3 \over 2}[e^{-j w_0 t} e^{-j{\pi \over 4}}] $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman