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== CT signal ==
 
<math>x(t) = 2 + cos({\frac{2\pi t}{3}})+ 4sin({\frac{5\pi t}{3}})\,</math>
 
<math>x(t) = 2 + cos({\frac{2\pi t}{3}})+ 4sin({\frac{5\pi t}{3}})\,</math>
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== Coefficients ==
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<math>cos({\frac{2\pi t}{3}}) = \frac{1}{2}e^({\frac{j2\pi t}{3}})</math>

Revision as of 17:08, 21 September 2008

CT signal

$ x(t) = 2 + cos({\frac{2\pi t}{3}})+ 4sin({\frac{5\pi t}{3}})\, $

Coefficients

$ cos({\frac{2\pi t}{3}}) = \frac{1}{2}e^({\frac{j2\pi t}{3}}) $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood