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| − | < | + | Given the periodic CT signal |
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| + | <math>\,x(t)=\frac{3\pi}{2}\cos(\frac{3\pi}{2}t+\pi)\sin(\frac{3\pi}{4}t+\frac{\pi}{2})\,</math> | ||
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| + | compute its Fourier series coefficients. | ||
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| + | == Answer == | ||
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| + | We can rewrite the signal <math>x(t)</math> as | ||
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| + | <math>\,x(t)=\frac{3\pi}{2}\,</math> | ||
Revision as of 09:23, 25 September 2008
Given the periodic CT signal
$ \,x(t)=\frac{3\pi}{2}\cos(\frac{3\pi}{2}t+\pi)\sin(\frac{3\pi}{4}t+\frac{\pi}{2})\, $
compute its Fourier series coefficients.
Answer
We can rewrite the signal $ x(t) $ as
$ \,x(t)=\frac{3\pi}{2}\, $
