(New page: == Define a CT Signal and its Fourier Series Coefficients == Periodic CT Signal: x(t) = 5cos(6t) + 2sin(3t) = <math> 5 * \frac {e^{j6t} + e^{-j6t}}{2} + 2 * \frac {e^{j3t} - e^{-j3t}}...)
 
(Define a CT Signal and its Fourier Series Coefficients)
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  e^{-j3t} </math>
 
  e^{-j3t} </math>
  
=
+
'''<math>a1 = \frac {t}{2}</math>''' 
 +
 
 +
'''<math>a-1 = \frac{5}{2}</math>'''
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 +
== a2= a-2 = j ==

Revision as of 06:28, 26 September 2008

Define a CT Signal and its Fourier Series Coefficients

Periodic CT Signal: x(t) = 5cos(6t) + 2sin(3t)

= $ 5 * \frac {e^{j6t} + e^{-j6t}}{2} + 2 * \frac {e^{j3t} - e^{-j3t}}{2j} $

= $ \frac{5}{2} * e^{j6t} - \frac{5}{2} * e^{-j6t} + j * e^{j3t} -j* e^{-j3t} $

$ a1 = \frac {t}{2} $

$ a-1 = \frac{5}{2} $

a2= a-2 = j

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Ph.D. 2007, working on developing cool imaging technologies for digital cameras, camera phones, and video surveillance cameras.

Buyue Zhang