(CT SIGNAL & ITS FOURIER COEFFICIENTS)
(CT SIGNAL & ITS FOURIER COEFFICIENTS)
Line 15: Line 15:
 
<math>a_-1 = \frac{j}{2}</math>
 
<math>a_-1 = \frac{j}{2}</math>
  
<math>a_2 = 1</math>
+
<'''math>a_2 = 1'''</math>
  
<math>a_-2 = 1</math>
+
<'''math>a_-2 = 1</math>'''

Revision as of 15:00, 23 September 2008

CT SIGNAL & ITS FOURIER COEFFICIENTS

Let the input signal be

$ x(t)=sint +2cos2t $

= $ \frac{e^{jt}-e^{-jt}}{2i} $+$ 2*\frac{e^{2jt}+{e^{-2jt}}}{2} $

= $ \frac{-j{e^{jt}}}{2}+\frac{j{e^{-jt}}}{2}+{e^{2jt}}+{e^{-2jt}} $

The coefficients are as follows:

$ a_1 = \frac{-j}{2} $

$ a_-1 = \frac{j}{2} $

<math>a_2 = 1</math>

<math>a_-2 = 1</math>

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood