Line 4: Line 4:
 
      
 
      
 
  =<math>3*\frac{e^jt+e^-jt}{2}+\frac{e^j2t-e^-j2t}{2}\,</math>
 
  =<math>3*\frac{e^jt+e^-jt}{2}+\frac{e^j2t-e^-j2t}{2}\,</math>
 +
=<math>3/2e^jt}-3/2e^{-jt}+1/2e^{j2t}-1/2e^{-j2t}</math>

Revision as of 10:32, 24 September 2008

Fourier series:

Input CT signal: x(t) = 3cost+sin2t
.
=$ 3*\frac{e^jt+e^-jt}{2}+\frac{e^j2t-e^-j2t}{2}\, $
=$ 3/2e^jt}-3/2e^{-jt}+1/2e^{j2t}-1/2e^{-j2t} $

Alumni Liaison

To all math majors: "Mathematics is a wonderfully rich subject."

Dr. Paul Garrett