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<math>a_{0} = \frac{2 + j}{4}</math> | <math>a_{0} = \frac{2 + j}{4}</math> | ||
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Revision as of 16:21, 26 September 2008
DT Signal:
1. Signal is periodic with N = 4
2. $ \sum_{k = 0}^{3}x[n] = (2 + j) $
3. for the given value of k, $ e^{jk2\pi} = 1\, $, then that $ a_{k} = \frac{1}{2}\, $
4. All other $ a_{k} = 0\, $
Solution
$ a_{0} = \frac{2 + j}{4} $
$ a_{0} = $
