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3.  for the given value of k, <math>e^{jk2\pi} = 1\,</math>, then that <math>a_{k} = \frac{1}{2}\,</math>  
 
3.  for the given value of k, <math>e^{jk2\pi} = 1\,</math>, then that <math>a_{k} = \frac{1}{2}\,</math>  
 +
 +
4.  All other <math>a_{k} = 0\,</math>
  
  

Revision as of 16:18, 26 September 2008

DT Signal:

1. Signal is periodic with N = 4

2. $ \sum_{k = 0}^{3}x[n] = (2 + j) $

3. for the given value of k, $ e^{jk2\pi} = 1\, $, then that $ a_{k} = \frac{1}{2}\, $

4. All other $ a_{k} = 0\, $


Solution

$ a_{0} = \frac{2 + j}{4} $

Alumni Liaison

Correspondence Chess Grandmaster and Purdue Alumni

Prof. Dan Fleetwood