Line 3: Line 3:
 
<math>x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\,</math>
 
<math>x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\,</math>
  
<math>x(t) = 4 * \frac{e^{j5\pit} - e^{-j5\pit}}{2} - (2+j)*\frac{e^{j3\pit} + e^{-j3\pit}}{2}\,</math>
+
<math>x(t) = 4 * \frac{e^{j5\pi t} - e^{-j5\pi t}}{2} - (2+j)*\frac{e^{j3\pi t} + e^{-j3\pi t}}{2}\,</math>

Revision as of 18:21, 22 September 2008

CT signal:

$ x(t) = 4\sin(5 \pi t) - (2 + j)\cos(3 \pi t)\, $

$ x(t) = 4 * \frac{e^{j5\pi t} - e^{-j5\pi t}}{2} - (2+j)*\frac{e^{j3\pi t} + e^{-j3\pi t}}{2}\, $

Alumni Liaison

BSEE 2004, current Ph.D. student researching signal and image processing.

Landis Huffman