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Put your content here . . .
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Case 1: AB and DE are parallel.
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That's easy.
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Case 2: they are not parallel. Then they meet, let X be the meeting point.
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  You get lots of similar triangles involving X, and with some algebra this should not be hard.
  
  

Revision as of 17:06, 22 September 2009

HW4-10MA460Fall2009

Case 1: AB and DE are parallel.

That's easy.

Case 2: they are not parallel. Then they meet, let X be the meeting point.

 You get lots of similar triangles involving X, and with some algebra this should not be hard.



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