(3. What is the decrypted message corresponding to (2,23,3)? (Write it as a text.))
(2. Can Eve decrypt the message without finding the inverse of the secret matrix?)
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==2. Can Eve decrypt the message without finding the inverse of the secret matrix? ==
 
==2. Can Eve decrypt the message without finding the inverse of the secret matrix? ==
She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message.
+
She can find what the secret matrix is. She can right a system of equations and solve for each component of the secret message.
 
:<math>\begin{pmatrix} 1 & 0 & 4 \\  0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\  d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\  0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix}</math>
 
:<math>\begin{pmatrix} 1 & 0 & 4 \\  0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\  d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\  0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix}</math>
 
:Multiply out
 
:Multiply out
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Solving These Equations yields the Secret Matrix
 
Solving These Equations yields the Secret Matrix
 
:<math>\begin{pmatrix}  -2/3 & 0 & 4 \\  0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix}</math>
 
:<math>\begin{pmatrix}  -2/3 & 0 & 4 \\  0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix}</math>
 +
but finding the secret message does not help her she needs to find the inverse of this matrix. This can be done the same way as above.
 +
 
==3. What is the decrypted message corresponding to (2,23,3)? (Write it as a text.)==
 
==3. What is the decrypted message corresponding to (2,23,3)? (Write it as a text.)==
 
<math>E*SM^-1=M \,</math>
 
<math>E*SM^-1=M \,</math>
 
:<math>\begin{pmatrix}  2 & 23 & 3\end{pmatrix}*\begin{pmatrix}  -2/3 & 0 & 4 \\  0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix}^{-1}=\begin{pmatrix}  2 & 23 & 5\end{pmatrix}</math>
 
:<math>\begin{pmatrix}  2 & 23 & 3\end{pmatrix}*\begin{pmatrix}  -2/3 & 0 & 4 \\  0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix}^{-1}=\begin{pmatrix}  2 & 23 & 5\end{pmatrix}</math>
 
"BWE"
 
"BWE"

Revision as of 09:58, 18 September 2008

Part C: Application of linearity

1. How can Bob decrypt the message?

Bob can get the message by multiplying the Message by the Secret Matrix inverted then decoding the numbers into letters. M*SM=E where M is message SM is the Secret Matrix and E is encrypted message. M=E*SM^-1

2. Can Eve decrypt the message without finding the inverse of the secret matrix?

She can find what the secret matrix is. She can right a system of equations and solve for each component of the secret message.

$ \begin{pmatrix} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix} $
Multiply out
$ a+4g=2, b+4h=0, c+4i=0 \, $
$ d=0, e=1, f=0 \, $
$ a+g=0, b+h=0, c+i=0 \, $

Solving These Equations yields the Secret Matrix

$ \begin{pmatrix} -2/3 & 0 & 4 \\ 0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix} $

but finding the secret message does not help her she needs to find the inverse of this matrix. This can be done the same way as above.

3. What is the decrypted message corresponding to (2,23,3)? (Write it as a text.)

$ E*SM^-1=M \, $

$ \begin{pmatrix} 2 & 23 & 3\end{pmatrix}*\begin{pmatrix} -2/3 & 0 & 4 \\ 0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix}^{-1}=\begin{pmatrix} 2 & 23 & 5\end{pmatrix} $

"BWE"

Alumni Liaison

has a message for current ECE438 students.

Sean Hu, ECE PhD 2009