(→2. Can Eve decrypt the message without finding the inverse of the secret matrix?) |
(→1. How can Bob decrypt the message?) |
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==Part C: Application of linearity== | ==Part C: Application of linearity== | ||
==1. How can Bob decrypt the message? == | ==1. How can Bob decrypt the message? == | ||
| − | Bob can get the message by multiplying the Message by the Secret | + | Bob can get the message by multiplying the Message by the Secret Matrix inverted then decoding the numbers into letters. |
| + | M*SM=E where M is message SM is the Secret Matrix and E is encrypted message. | ||
| + | M=E*SM^-1 | ||
| + | |||
==2. Can Eve decrypt the message without finding the inverse of the secret matrix? == | ==2. Can Eve decrypt the message without finding the inverse of the secret matrix? == | ||
She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message. | She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message. | ||
Revision as of 09:45, 18 September 2008
Part C: Application of linearity
1. How can Bob decrypt the message?
Bob can get the message by multiplying the Message by the Secret Matrix inverted then decoding the numbers into letters. M*SM=E where M is message SM is the Secret Matrix and E is encrypted message. M=E*SM^-1
2. Can Eve decrypt the message without finding the inverse of the secret matrix?
She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message.
- $ \begin{pmatrix} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix} $
- Multiply out
- $ a+4g=2, b+4h=0, c+4i=0 \, $
- $ d=0, e=1, f=0 \, $
- $ a+g=0, b+h=0, c+i=0 \, $
Solving These Equations yields the Secret Matrix
- $ \begin{pmatrix} -2/3 & 0 & 4 \\ 0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix} $
Not finished/working yet
