(→2. Can Eve decrypt the message without finding the inverse of the secret matrix?) |
(→2. Can Eve decrypt the message without finding the inverse of the secret matrix?) |
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Bob can get the message by multiplying the Message by the Secret message then decoding the numbers into letters. | Bob can get the message by multiplying the Message by the Secret message then decoding the numbers into letters. | ||
==2. Can Eve decrypt the message without finding the inverse of the secret matrix? == | ==2. Can Eve decrypt the message without finding the inverse of the secret matrix? == | ||
| − | + | She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message. | |
:<math>\begin{pmatrix} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix}</math> | :<math>\begin{pmatrix} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix}</math> | ||
:Multiply out | :Multiply out | ||
Revision as of 09:43, 18 September 2008
Part C: Application of linearity
1. How can Bob decrypt the message?
Bob can get the message by multiplying the Message by the Secret message then decoding the numbers into letters.
2. Can Eve decrypt the message without finding the inverse of the secret matrix?
She can find what the secret matrix is, but she has to invert the Seceret Matrix to encrypt the matrix. She can right a system of equations and solve for each component of the secret message.
- $ \begin{pmatrix} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{pmatrix}\begin{pmatrix} a & b & c \\ d & e & f \\ g & h & i \end{pmatrix}=\begin{pmatrix} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{pmatrix} $
- Multiply out
- $ a+4g=2, b+4h=0, c+4i=0 \, $
- $ d=0, e=1, f=0 \, $
- $ a+g=0, b+h=0, c+i=0 \, $
Solving These Equations yields the Secret Matrix
- $ \begin{pmatrix} -2/3 & 0 & 4 \\ 0 & 1 & 0 \\ 2/3 & 0 & -1 \end{pmatrix} $
Not finished/working yet
