Revision as of 09:47, 18 September 2008 by Cztan (Talk)

Info from question

$ \left[ \begin{array}{ccc} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{array} \right] \times \left[ \begin{array}{ccc} X \end{array} \right] = \left[ \begin{array}{ccc} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{array} \right] $

1. How can Bob decrypt the message?

Since Bob already knows the matrix [X] and the encrypted matrix, all he has to do to find the original matrix is to invert [X] and multiply with the encrypted matrix.

2. Can Eve decrypt the message without finding the inverse of the secret matrix?

The easiest way would be for her to find the inverse of the secret matrix. I think she can still find it somehow using linearity but I really can't remember how to do it.

3. What is the decrypted message corresponding to (2,23,3)?

First we find the matrix [X]:

$ [X] = \left[ \begin{array}{ccc} 1 & 0 & 4 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \end{array} \right]^{-1} \times \left[ \begin{array}{ccc} 2 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{array} \right] $

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva