HW3.B Xujun Huang ECE301Fall2008mboutin - Rhea
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Revision as of 16:46, 18 September 2008 by
Huang122
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$ e^2jt = te^(-2jt) $
$ e^2jt = te^(-2jt) $
=>
$ \cos(2t)=\frac{e^2jt+e^(-2jt)}{2} $
=
$ \frac{1}{2} $
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