(New page: <math>e^{2jt}</math> yields <math>te^{-2jt}</math>)
 
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<math>e^{2jt}</math> yields <math>te^{-2jt}</math>
 
<math>e^{2jt}</math> yields <math>te^{-2jt}</math>
 +
and
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<math>e^{-2jt}</math> yields <math>te^{2jt}</math>
 +
 +
and the system is linear
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 +
since Euler's formulat states that : <math>e^{ix} = \cos x + i\sin x \!</math>

Revision as of 15:47, 19 September 2008

$ e^{2jt} $ yields $ te^{-2jt} $ and $ e^{-2jt} $ yields $ te^{2jt} $

and the system is linear

since Euler's formulat states that : $ e^{ix} = \cos x + i\sin x \! $

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