Revision as of 08:02, 18 September 2008 by Serdbrue (Talk)

Basics of Linearity

Given

$ e^{2 x i}=t e^{-2 x i}\, $
$ e^{-2 x i}=t e^{2 x i}\, $
$ \cos x = \dfrac{e^{i x}+e^{-i x}}{2} $
$ \cos 2x = \dfrac{e^{2 i x}+e^{-2 i x}}{2} $

The Systems response to $ \cos 2x $ is $ \ \dfrac{t e^{-2 i x} + t e^{2 i x}}{2} $

$ \dfrac{t e^{-2 i x} + t e^{2 i x}}{2} = t\cos 2t $

Alumni Liaison

Recent Math PhD now doing a post-doctorate at UC Riverside.

Kuei-Nuan Lin