(Time Invariant System)
(Stable System)
 
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==Stable System==  
 
==Stable System==  
1-        Give a formal definition of a “memoryless system”. Give a formal definition of a “system with memory”.
 
  
2-        Give a formal definition of a “causal system”. Give a formal definition of a non-causal system.
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A system is stable if bounded inputs yield bounded outputs.
  
3-        Give a formal definition of a “linear system”. Give a formal definition of a “non-linear system”.
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A system is not stable if bounded inputs yield unbounded outputs.
 
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4-        Give a formal definition of a “time invariant system”. Give a formal definition of a “time variant system”.
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5-        Give a formal definition of a “stable system”. Give a formal definition of an unstable system.
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Latest revision as of 17:50, 17 September 2008

Memoryless System

A memoryless system is a system for which for any real number $ t_0 $, the output at $ t_0 $ depends only on that value of t.

A system with memory is a system whose output depends on the value $ t_0 $ as well as another value of t for any given $ t_0 $

Causal System

A system is causal if the output at any given time only depends on the input in present and past (not the future)

A system is not causal if the output at any given time depends on input in the future.

Linear System

A system is linear if for any complex constants a and b and for any inputs $ x_1(t) $ and $ x_2(t) $ yielding output $ y_1(t) $ and $ y_2(t) $ respectively, the response is $ a*x_1(t)+b*x_2(t) ==> [SYSTEM] ==> a*y_1(t) + b*y_2(t) $

A system is nonlinear if for any complex constants a and b and for any inputs $ x_1(t) $ and $ x_2(t) $ yielding output $ y_1(t) $ and $ y_2(t) $ respectively, the response is $ a*x_1(t)+b*x_2(t) ==> [SYSTEM] ==> z(t) $ where $ z(t) $ is NOT the constants a and b multiplied by the outputs $ y_1(t) $ and $ y_2(t) $

Time Invariant System

A system is called time invariant if for any input signal x(t) yielding output y(t) and for any time $ t_0 $ the output to the shifted input $ x(t-t_0) $ is the shifted output $ y(t-t_0) $.

A system is not time invariant if shifting the input does not yield the same output shifted by the same amount.

Stable System

A system is stable if bounded inputs yield bounded outputs.

A system is not stable if bounded inputs yield unbounded outputs.

Alumni Liaison

Basic linear algebra uncovers and clarifies very important geometry and algebra.

Dr. Paul Garrett