(New page: <math>P(red | 1 red roll) = P(red & 1 red roll) / P(1 red roll)</math> Start by calculating the probibility of each dice being picked times its probibility of rolling 2 reds <math>= (1/3)...)
 
 
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<math>P(red | 1 red roll) = P(red & 1 red roll) / P(1 red roll)</math>
+
P(red | 1 red roll) = P(red & 1 red roll) / P(1 red roll)
  
 
Start by calculating the probibility of each dice being picked times its probibility of rolling 2 reds
 
Start by calculating the probibility of each dice being picked times its probibility of rolling 2 reds
<math>= (1/3)(1/6)(1/6) + (1/3)(2/6)(2/6) + (1/3)(3/6)(3/6)</math>
+
 
 +
= (1/3)(1/6)(1/6) + (1/3)(2/6)(2/6) + (1/3)(3/6)(3/6)
  
 
then you simply take your answer over the aswer to part a to finish the formula and get your answer.
 
then you simply take your answer over the aswer to part a to finish the formula and get your answer.

Latest revision as of 06:44, 17 September 2008

P(red | 1 red roll) = P(red & 1 red roll) / P(1 red roll)

Start by calculating the probibility of each dice being picked times its probibility of rolling 2 reds

= (1/3)(1/6)(1/6) + (1/3)(2/6)(2/6) + (1/3)(3/6)(3/6)

then you simply take your answer over the aswer to part a to finish the formula and get your answer.

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva