(New page: Someone tell me if i am thinking about this wrong. 1) .001^k = p[total outage on a given day] 2) 365*0.001^k = p[total outage at least once during the year] 3) we want 365*0.001^k to be l...)
 
Line 2: Line 2:
  
 
1) .001^k = p[total outage on a given day]
 
1) .001^k = p[total outage on a given day]
 +
 
2) 365*0.001^k = p[total outage at least once during the year]
 
2) 365*0.001^k = p[total outage at least once during the year]
 +
 
3) we want 365*0.001^k to be less than or equal to 0.001
 
3) we want 365*0.001^k to be less than or equal to 0.001
 +
 
4) 365*0.001^k = 0.001
 
4) 365*0.001^k = 0.001
 +
 
5) k=1.8541
 
5) k=1.8541

Revision as of 05:52, 15 September 2008

Someone tell me if i am thinking about this wrong.

1) .001^k = p[total outage on a given day]

2) 365*0.001^k = p[total outage at least once during the year]

3) we want 365*0.001^k to be less than or equal to 0.001

4) 365*0.001^k = 0.001

5) k=1.8541

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Sees the importance of signal filtering in medical imaging

Dhruv Lamba, BSEE2010