(New page: Take P,The probability of not getting connected on one day = (0.001)<math>^k</math>) |
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| − | Take P,The probability of not getting connected on one day = (0.001)<math>^k</math> | + | Take P,The probability of not getting connected on any one day = (0.001)<math>^k</math> |
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| + | (1-(.001<math>^k</math>))<math>^365</math> Serves the condition "atlest" | ||
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| + | Therefore 1-(1-(.001<math>^k</math>))<math>^365</math> Tells us the proability of total outrage happening "atleast" once a year. | ||
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| + | The above expression should be lesser or eual to 0.001....so solve the equation from thereon!! | ||
Revision as of 19:13, 16 September 2008
Take P,The probability of not getting connected on any one day = (0.001)$ ^k $
(1-(.001$ ^k $))$ ^365 $ Serves the condition "atlest"
Therefore 1-(1-(.001$ ^k $))$ ^365 $ Tells us the proability of total outrage happening "atleast" once a year.
The above expression should be lesser or eual to 0.001....so solve the equation from thereon!!
