Revision as of 14:12, 11 September 2008 by Anders89 (Talk)

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Part A

This system is not time invariant because it depends on the time shift of the function. This System goes in the order of:

X1(t) --> delay --> System --> multiplication and addition --> Y(t)

However, if it goes in this order:

X1(t) --> multiplication and addition --> system --> delay --> Y(t)

Then the two outputs would not be equal. The coefficients would be different.


Part B

Alumni Liaison

Meet a recent graduate heading to Sweden for a Postdoctorate.

Christine Berkesch