(New page: == Part A == This system is not time invariant because it depends on the time shift of the function. This System goes in the order of: X1(t) --> delay --> System --> multiplication ...) |
(→Part B) |
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== Part B == | == Part B == | ||
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| + | With only inputing | ||
| + | |||
| + | x[n] = u[n] | ||
| + | |||
| + | Then the coefficient of the output is just the square of the time time delay value, which this time delay would be "1". | ||
| + | |||
| + | So u^2 is just (1)^2 = 1 | ||
| + | |||
| + | So the output of the signal is: | ||
| + | |||
| + | y[n] = (u * 1)[n - 1] = u[n - 1] | ||
Latest revision as of 14:16, 11 September 2008
Part A
This system is not time invariant because it depends on the time shift of the function. This System goes in the order of:
X1(t) --> delay --> System --> multiplication and addition --> Y(t)
However, if it goes in this order:
X1(t) --> multiplication and addition --> system --> delay --> Y(t)
Then the two outputs would not be equal. The coefficients would be different.
Part B
With only inputing
x[n] = u[n]
Then the coefficient of the output is just the square of the time time delay value, which this time delay would be "1".
So u^2 is just (1)^2 = 1
So the output of the signal is:
y[n] = (u * 1)[n - 1] = u[n - 1]
