(6.(A))
(6.(A))
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The output signals are different each other. So this is not time-invariant.
 
The output signals are different each other. So this is not time-invariant.
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== 6.(B) ==

Revision as of 18:47, 10 September 2008

6.(A)

This is not time-invariant.

1. input($ /delta[n-k] $) -> system -> time delay (1) -> output : $ (k+1)^2\delta[n-(k+2)] $
2. input($ /delta[n-k] $) -> time delay (1) -> system -> output : $ (k+2)^2\delta[n-(k+2)] $

The output signals are different each other. So this is not time-invariant.


6.(B)

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Sean Hu, ECE PhD 2009