Revision as of 20:30, 11 September 2008 by Jkubasci (Talk)

Part A: Can the system be time invariant?

The system cannot be time invariant.


For instance, the input

$ \,X_0[n]=\delta [n]\, $

yields the output

$ \,Y_0[n]=\delta [n-1]\, $

Thus,

$ \,Y_0[n-1]=\delta [n-2]\, $


However, the input

$ \,X_0[n-1]=\delta [n-1]=X_1[n]\, $

yields the output

$ \,Y_1[n]=4\delta[n-2]\, $


Since these two are not equal

$ \,\delta [n-2]\not= 4\delta[n-2]\, $

the system is time variant (by not fitting the definition of time invariance).

Part B: Find input given output

LAWL

Alumni Liaison

Ph.D. on Applied Mathematics in Aug 2007. Involved on applications of image super-resolution to electron microscopy

Francisco Blanco-Silva