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6 a) The system cannot be time-invariant.
 
6 a) The system cannot be time-invariant.
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<math>X_k[n] = \delta[n - k] \rightarrow system \rightarrow Y_k[n] = (k + 1)^2 \delta[n - (k + 1)]</math>
 
<math>X_k[n] = \delta[n - k] \rightarrow system \rightarrow Y_k[n] = (k + 1)^2 \delta[n - (k + 1)]</math>
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Let us apply a time-delay of <math>n_0</math> to the system.
 
Let us apply a time-delay of <math>n_0</math> to the system.
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System followed by time-delay:  
 
System followed by time-delay:  
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<math>\delta[n - k] \rightarrow time-delay \rightarrow \delta[n-(k + n_0)] \rightarrow system \rightarrow (k + n_0 + 1)^2 \delta[n - (k + n_0 + 1)]</math>
 
<math>\delta[n - k] \rightarrow time-delay \rightarrow \delta[n-(k + n_0)] \rightarrow system \rightarrow (k + n_0 + 1)^2 \delta[n - (k + n_0 + 1)]</math>
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Since the outputs don't match, the system is not time-invariant.

Revision as of 16:46, 11 September 2008

6 a) The system cannot be time-invariant.


$ X_k[n] = \delta[n - k] \rightarrow system \rightarrow Y_k[n] = (k + 1)^2 \delta[n - (k + 1)] $


Let us apply a time-delay of $ n_0 $ to the system.


System followed by time-delay:

$ \delta[n - k] \rightarrow system \rightarrow (k + 1)^2 \delta[n - (k + 1)] \rightarrow time-delay \rightarrow (k + 1)^2 \delta[n - n_0 -(k + 1)] = (k + 1)^2 \delta[n -(k + 1 +n_0)] $


Time-delay followed by system:

$ \delta[n - k] \rightarrow time-delay \rightarrow \delta[n-(k + n_0)] \rightarrow system \rightarrow (k + n_0 + 1)^2 \delta[n - (k + n_0 + 1)] $

Since the outputs don't match, the system is not time-invariant.

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