(New page: ==Problem 6a== This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of...)
 
 
Line 2: Line 2:
  
 
This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant.
 
This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant.
 +
 +
==Problem 6b==
 +
 +
The table indicates that if the input is <math>\delta[n]</math> then the output is <math>\delta[n-1]</math>. Therefore, if the system is linear, for the output to be <math>u[n-1]</math>, the input then needs to be <math>u[n]</math>.

Latest revision as of 20:57, 11 September 2008

Problem 6a

This system cannot be time-invariant because the function of the output has a constant k that gets changed everytime one selects a value of k. This changes the amplitude of the output function, making it not correspond to the input function and therefore cannot be time-invariant.

Problem 6b

The table indicates that if the input is $ \delta[n] $ then the output is $ \delta[n-1] $. Therefore, if the system is linear, for the output to be $ u[n-1] $, the input then needs to be $ u[n] $.

Alumni Liaison

ECE462 Survivor

Seraj Dosenbach